Question

the sum of three consecutive multiples of 8 is 888 find the multiples

Answer 1

suppose three multiples are x-1,x,x+1 th multiples of 8.

Their sum is 888. So, 8(x-1)+8x+8(x+1)=888

24x=888

3x=111.

x=111/3=37.
Multiples are:

8(x-1)=8*36=288
8*37=296

8*38=304.

Answer 2

Here is your answer

Let,
The three consecutive multiples of 8 be x, x + 8 and x + 16.

x + (x + 8) + (x + 16) = 888  (Given)

⇒ 3x + 24 = 888

⇒ 3x = 888 – 24

⇒ 3x = 864

⇒ x = 288


Number are:-

x=288

x + 8 = 288 + 8 = 296

x + 16 = 288 + 16 = 304


Hence,

The three consecutive multiples of 8 are 288, 296 and 304.

Hope it helps you