Math, asked by guneetkaur1378, 3 months ago

The sum of three consecutive multiples of 8 is 888. Find the multiples??

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Answers

Answered by ShubhangChoudhary
2

Answer:

288, 296, 304 Please Mark Me as Brainliest

Step-by-step explanation:

Let the first multiple of 8 be 8x

.

The second consecutive multiple of 8 be 8(x+1)

.

The third consecutive multiple of 8 be 8(x+2)

.

It is given that the sum of all the three consecutive multiples of 8 is 888.

Then writing as follows:

⇒8x+8(x+1)+8(x+2)=888

⇒8x+8x+8x+8+16=888

⇒24x+24=888

⇒24x=888−24

⇒24x=864

⇒x=86424

⇒x=36

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . (a)

Therefore the first multiple of 8 is 8x

, by substituting the value of x in the equation we get,

⇒8×36=288

.

Therefore the second multiple of 8 is 8(x+1)

, by substituting the value of x in the equation we get,

⇒8(36+1)=296

.

Therefore the second multiple of 8 is 8(x+2)

, by substituting the value of x in the equation we get, ⇒8(36+2)=304

.

If we add up all the three consecutive multiples of 8 we get 288+296+304 = 888

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