Question

The sum of three consecutive multiples of 8 is 888 find the multiples?​

Answer 1

Answer:

let one multiple be y

other be y+8

third be y+16

y+y+8+y+16

3y+21=888

3y = 888-21

3y = 867

y = 289

other two numbers are 297 and 305

Answer 2

Answer: The three consecutive multiples are 288, 296, and 304.

Let us simplify the given problem by nature of multiples of a number.

Explanation:

The multiples of 8 are in the format of 8n.

Let the three consecutive multiples of 8 are 8n - 8, 8n, and 8n + 8

Given that the sum of these multiples is 888.

⇒ 8n - 8 + 8n + 8n + 8 = 888

⇒ 8n + 8n + 8n = 888

⇒ 24n = 888

⇒ n = 888 / 24

⇒ n = 37

⇒ 8n = 296

The multiples of 8 are

• 8n - 8 = 296 - 8 = 288
• 8n = 296
• 8n + 8 = 296 + 8 = 304

Thus, the three consecutive multiples of 8 are 288, 296, and 304.

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