Question

The sum of three consecutive multiples of 8 is 888. Find the multiples.​

Answer 1

☯️ Let the three consecutive multiples of 8 be 8x,8(x + 1) and 8(x + 2).

Need to Find : The Miltuples.

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8x + 8(x+1) + 8(x+2) = 888

$\longrightarrow$ 8 (x + x+1 + x+2) = 888 (Taking 8 as common)

$\longrightarrow$ 8 (3x + 3) = 888

$\longrightarrow$ 3x + 3 = 888/8

$\longrightarrow$ 3x + 3 = 111

$\longrightarrow$ 3x = 111 – 3

$\longrightarrow$ 3x = 108

$\longrightarrow$ x = 108/3

$\longrightarrow$ x = 36

Therefore, the three consecutive multiples of 8 are,

$\longrightarrow$ 8x = 8 × 36 = 288

$\longrightarrow$ 8(x + 1) = 8 × (36 + 1) = 8 × 37 = 296

$\longrightarrow$ 8(x + 2) = 8 × (36 + 2) = 8 × 38 = 304

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Hope it helps ya!! :)

Answer 2

Answer:

The three consecutive multiples of 8 are,

• 8x = 8 × 36 = 288

• 8(x + 1) = 8 × (36 + 1) = 8 × 37 = 296

• 8(x + 2) = 8 × (36 + 2) = 8 × 38 = 304