Question

The sum of three consecutive multiples of 8 is 888.Find the multiples.​

Answer 1

Answer:

let three consecutive multiples of 8

8x, 8(x+1),8(x+2)

Sum= 8x +8(x+1),8(x+2)=888

8(x+x+x+1+2)=888

3(x+1)=111

x+1=111/3

x+1=37

First multiple= 8x= 8X36=288

Second multiple= 8(x+1)=8X37=296

Third multiple=8(x+2)=8X38=304

Step-by-step explanation:

I think it's correct

make me brainliest

Answer 2

Answer:

let the first multiple of 8 be 8x. Also the third consecutive multiple of 8 will be 8(x+2). => x = 36. If we sum up these three multiples i.e (288 + 296 + 304) we get 888.