The sum of three consecutive multiples of 8 is 888. Find the multiples
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Answer:
Answer: The three consecutive multiples are 288, 296, and 304.
Let us simplify the given problem by nature of multiples of a number.
Explanation:
The multiples of 8 are in the format of 8n.
Let the three consecutive multiples of 8 are 8n - 8, 8n, and 8n + 8
Given that the sum of these multiples is 888.
⇒ 8n - 8 + 8n + 8n + 8 = 888
⇒ 8n + 8n + 8n = 888
⇒ 24n = 888
⇒ n = 888 / 24
⇒ n = 37
⇒ 8n = 296
The multiples of 8 are:
8n - 8 = 296 - 8 = 288
8n = 296
8n + 8 = 296 + 8 = 304
Thus, the three consecutive multiples of 8 are 288, 296, and 304.
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