Question

The sum of three consecutive multiples of 8 is 888.Find the multiples

Answer 1

$Let \: the \: three \: consecutive \: multiples \: be \: x \\ \\ x + (x + 8) + (x + 16) = 888 \\ \\ = > 3x + 24 = 888 \\ \\ 3x = 888 - 24 \\ \\ 3x = 864 \\ \\ x = \frac{864}{3} \\ \\ x = 288 \\ \\ 1st \: \: multiples = x = 288 \\ \\ 2nd \: multiples = x + 8 = 288 + 8 = 296 \\ \\ 3rd \: multiples = x + 16 = 288 + 16 = 304 \\ \\ Hence, \: the \: three \: consecutive \: multiples \: are :- \: \: \: \: \: \: \: \: \: 288 \: ,296 \: and \: 304$

Answer 2

$\bf \large \it{Hey \: user!!!}$

according to the question, the sum of three consecutive multiples of 8 is 888.

let the three consecutive multiples be x, x + 8 and x + 16

therefore x + x + 8 + x + 16 = 888
>> 3x + 24 = 888
>> 3x = 888 - 24
>> 3x = 864
>> x = 964/3
>> x = 288

hence, the three consecutive multiples are :-

x = 288, x + 8 = 288 + 8 = 296 and x + 16 = 288 + 16 = 304

$\large \bf \it{Cheers!!!}$