Question

the sum of three consecutive multiples of 8 is 888. find the multiple of 8

Answer 1

Let consecutive multiples of 8 be x,x+8 , x+16

x+8+x+16+x=888
3x+24=888
3x=864
x=288

numbers are 288,296,304


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Answer 2

the three consecutive integers are x,x+1,x+2

and the three consecutive multiples of 8 are
x,x+8,x+16

thus,

x+x+8+x+16 = 888

3x+24 = 888

3x= 888-24

3x = 864

x = 288

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