Question

The sum of three consecutive multiples of 8 is 888. Find the multiples?​

Answer 1

Let the three multiples be 8(x-1) , 8(x) , 8(x+1)

Their sum is 888

so

8(x-1) + 8x + 8(x+1) = 888

8x-8 + 8x + 8x+8 = 888

24x = 888

x = 888/24 = 111/3 = 37

Therefore the three numbers are

1. 8(x-1) = 8(36) = 288

2. 8x = 8*37 = 296

3. 8(x+1) = 8*38 = 304

Hope it helps

Answer 2

$\huge\boxed{\red{\bold{Solution}}}$

✍ let the three consecutive number be x, (x +8) , (x + 16 )..✌

⭐ x + (x +8)+(x+16) = 888

=> x + x+8 + x + 16 = 888

=> 3x + 8 + 16 = 888

=> 3x + 24 = 888

=>3x = 888- 24

=> 3x = 864

=> x = 864/ 3

=> x = 288

So , x = 288

⭐ (x + 8) = 288 + 8 = 296

⭐( x + 16) = 288 + 16 = 304

Hence ,

Three consecutive number be 288, 296 and 304..