Question

the sum of three consecutive multiples of 8 is 888. multiple are​

Answer 1

Given:

Sum of three consecutive multiples of 8 = 888

To Find:

The multiples in the statement.

Solution:

Let us consider the three multiples as $8x, \: 8(x+1)$ and $8(x+2)$

According to the question,

$8x+ 8(x+1)+8(x+2) =888\\\implies 8(x+x+1+x+2)=888\\\implies 8(3x+3)=888$

Solving x,

$\implies 3x+3=\frac{888}{8} \\\implies 3x+3=111\\\implies 3x=111-3\\\implies 3x=108\\x=\frac{108}{3} \\:\implies {x=36}$

Therefore, finding the three consecutive multiples:

$8x=8 \times 36=\boxed{288}$

$8(x+1)=8\times (36+1)=8\times 37= \boxed{296}$

$8(x+2)=8 \times (36 +2)=8 \times 38= \boxed {304}$

Thus, the three consecutive multiples are 288, 296 and 304.

Answer 2

HERE IS UR ANSWER.....

Let the numbers be x, x+8 and x+16

x+x+8+x+16 = 888

3x+ 24 = 888

3x = 888-24

3x = 864

x = 864÷3

x = 288

The numbers are 288, 296 and 304.

Hope it helps u...