Question

The sum of three consecutive multiples of 8 is equal to eight times the sum of the first to
consecutive multiples of 6. Find each of the three multiples of 8.​

Answer 1

Hello Mate,

Here is your answer,

We Know,

Let First three consecutive multiples of 8 are:

(x + 8) , (x + 16) and (x + 24)

Let First two consecutive multiples of six are:

(x + 6) and (x + 12)

So the sum of three consecutive multiples of 8 is equal to 8 times the sum of first two consecutive multiples of 6.

Meaning,

(x + 8) + (x + 16) + (x + 24) = 8 [(x + 6) + (x + 12)]

(3x + 48) = (2x + 18)

3x - 2x = 48 - 18

x = 30

The three multiples of 8 are:

x + 8

= 30 + 8

= 38

x + 16

= 30 + 16

= 46

x + 24

= 30 + 24

= 54

Hope it helps:)

Answer 2

Answer:

Step-by-step explanation:

8x+16x+24x=8×18

48x=144

x=144÷48

x=3

8x=24

16x=32

24x=40