Question

The sum of three consecutive multiples of 8
is equal to eight times the sum of the first two
consecutive multiples of 6. Find each of the three
multiples of 8.​

Answer 1

Answer:

Hi friends

Step-by-step explanation:

(x + 8) , (x + 16) and (x + 24)

Let First two consecutive multiples of six are:

(x + 6) and (x + 12)

So the sum of three consecutive multiples of 8 is equal to 8 times the sum of first two consecutive multiples of 6.

Meaning,

(x + 8) + (x + 16) + (x + 24) = 8 [(x + 6) + (x + 12)]

(3x + 48) = (2x + 18)

3x - 2x = 48 - 18

x = 30

The three multiples of 8 are:

x + 8

= 30 + 8

= 38

x + 16

= 30 + 16

= 46

x + 24

= 30 + 24

= 54

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