The sum of three consecutive multiples of 8is 888 . Find the multiples
Answers
Answered by
12
Let the first no. be x
Let the second no. be x+8
Let the third no. be x+8+8
x+x+8+x+8+8=888
3x+24=888
3x=888-24
3x=864
x=864/3
x=288
x=288
x+8=296
x+8+8=304
Let the second no. be x+8
Let the third no. be x+8+8
x+x+8+x+8+8=888
3x+24=888
3x=888-24
3x=864
x=864/3
x=288
x=288
x+8=296
x+8+8=304
Answered by
6
Let consecutive multiples of 8 be
x, x+8, x+8+8
Their sum = 888
equation formed= x+x+8+x+8+8 = 888
so,
(x+x+x)+(8+8+8) = 888
3x + 24 = 888
3x = 888-24
3x = 864
x= 864/3
x= 288
so the numbers are
x=288
x+8= 288+8 = 296
x+8+8 = 288+8+8 = 304
Hope it helps ^_^
x, x+8, x+8+8
Their sum = 888
equation formed= x+x+8+x+8+8 = 888
so,
(x+x+x)+(8+8+8) = 888
3x + 24 = 888
3x = 888-24
3x = 864
x= 864/3
x= 288
so the numbers are
x=288
x+8= 288+8 = 296
x+8+8 = 288+8+8 = 304
Hope it helps ^_^
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