The sum of three consecutive multiples of 9 is 108 find the number??
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Answered by
31
here is ur answer
let the no . be
a ,a+9 and a+18
sum of these r 108
3a+27=108
3a=81
a=27
first no. is 27
2nd is 36
3rd is 45
let the no . be
a ,a+9 and a+18
sum of these r 108
3a+27=108
3a=81
a=27
first no. is 27
2nd is 36
3rd is 45
burningdragon050509:
27+36+45=108
Answered by
13
answer is 45 , 60 , and 75
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