the sum of three consecutive multiples of 9 is 270.Find these multiples. Frame the equation and find them.
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Let the smallest multiple of 9 be 9x
so, 9x+9(x+1)+9(x+2)=270
9x+9x+9+9x+18=270
27x+27=270
27x=270-27
27x=243
x=243/27
x=9
so the multiples are
9×9=81
9×10=90
9×11=99
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