Question

the sum of three consecutive multiples of 9 is 270 find the smallest multiple​

Answer 1

The three consecutive multiples of 9 is 81,81+9,81+18

Answer 2

Answer:

1st consecutive =9×x=9x

2nd consecutive =9(x+1)=9x+9

3rd consecutive =9 (x+2)=9x+18

sum=270

9x+9x+9+9x+18=270

27x+27=270

27x=270-27

27x=243

x=243/27

x=9

1st consecutive =9x=9×9=81

2nd consecutive =9x+9=9×9+9=90

3rd consecutive =9x+18=9×9+18=99