Question

the sum of three consecutive multiples of 9 is 327. find these multiples​

Answer 1

Answer:

100,109,118

explanation:

let the three consecutive multiples of 9 be

x, x+9,x+18

therefore, (x)+(x+9)+(x+18)=327

→ 327 = x + x + 9 + x + 18

=3x +27

327-27 = 3x

300= 3x

300/3= x

100=x

therefore the three consecutive multiples of 9 are. x=100

x+9=100+9

=109

x+18=100+18

=118

Hope it helps

Please mark as brainliest