Question

THE SUM OF THREE CONSECUTIVE MULTIPLES OF 9 IS 378. FIND THE THREE MULTIPLES?

Answer 1

Let the 3 consecutive multiples of 9 be n , n+1 and n+2. Given: 9n + 9(n+1)+ 9(n+2) =378 9n+9n +9+9n +18 =378 27n + 27=378 27n= 357 n= 357/27= 13 Thus the 3no's are: 9n ,9(n+1) and 9(n+2) 9*13, 9*14 and 9*15 i.e; 117, 126 and 135

Answer 2

solution :-

Given:-
The sum of three consecutive multiples of 9 is 378.

Let the first number be x.

second number= x +9

Third number = x+9+9 = x+18

Now

x + x+ 9 + x+18 = 378
=>3x + 27 = 378
=>3x = 378 -27
=>x = 351/3
=>x = 117

first number = 117

second number = 117+9 = 126

third number = 117+18 = 135

so 117, 126 and 135 are the 3 consecutive multiples of 9 whose sum is 378. 

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