Question

The sum of three consecutive multiples of 9 is 432. The multiples are

Answer 1

Answer:

Let first multiple = X

second = X+9

third = X+18

According to Ques:

X+X+9+X+18=432

(X+X+X)+(9+18)=432

3x+27=432

3x=432-27

3x=405

X=405/3

X=135

so,multiples are:

1=135

2=135+9=144

3=135+18=153

Answer 2

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