Question

The sum of three consecutive multiples of 9 is 567. Find the largest of these numbers.​

Answer 1

1. Let three consecutive multiple of 9 are x,x+1,x+2
2. then , (x+x+1+x+2)×9=567
3. x=20
4. 1st= 180,2nd = 189,3rd= 198

Answer 2

Answer:

Let the numbers be x,x+9(9×1),x+18(9×2)

x+x+9+x+18=567

3x+27=567

3x=567-27

=540

x=540/3

=180

x=180

x+9=180+9

=189

x+18=180+18

=198

Hope it helps,I think it's the correct answer

Let me check

180+189+198=567

Its right