Math, asked by varnikac49, 5 hours ago

The sum of three consecutive multiples of 9 is 567. Find the largest of these numbers.​

Answers

Answered by geetkappur
1

Answer:

largest number is 198

Step-by-step explanation:

let 3 consecutive multiples of 9 be 9x, 9(x+1) and 9(x+2)

as per question,

9x + 9(x+1) + 9(x+2) =567

9x + 9x+9 +9x + 18 = 567

27x + 27 = 567

27x = 567-27

27x = 540

x = 540/27

x = 20

hence, the 3 numbers are

9x = 9*20 = 180

9(x+1) = 9*21 = 189

9(x+2) = 9*22 = 198

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