The sum of three consecutive multiples of 9 is 567. Find the largest of these numbers.
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Answer:
largest number is 198
Step-by-step explanation:
let 3 consecutive multiples of 9 be 9x, 9(x+1) and 9(x+2)
as per question,
9x + 9(x+1) + 9(x+2) =567
9x + 9x+9 +9x + 18 = 567
27x + 27 = 567
27x = 567-27
27x = 540
x = 540/27
x = 20
hence, the 3 numbers are
9x = 9*20 = 180
9(x+1) = 9*21 = 189
9(x+2) = 9*22 = 198
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