The sum of three consecutive multiples of 9 is 795. Find these multiples.
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Answered by
12
If p is a multiple of 9, the next multiple is p+9.
According to the question:
⟹p+(p+9)+(p+18)=135
⟹3p+27=135
⟹3p=135−27
⟹3p=108
⟹p=36
Multiples are p,p+9,p+18
36,45,54
Answered by
0
Answer:
HERE IS YOUR ANSWERE
Step-by-step explanation:
Let multiplies be a,a+9 anda+18
a+a+9+a+18=795
3a+27=795
3a=795-27
3a=768
a=768÷3
a=256
a+9=256
a+18=274
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