Question

The sum of three consecutive multiples of 9 is 81. The smallest number is __________.

Answer 1

Answer:

let the no.be x, so that

$\huge \mathfrak {x + x + 3 + x + 6 = 81}$

$\huge \mathfrak {or, 3x + 9 = 81}$

$\huge \mathfrak {or, 3x = 81-9}$

$\huge \mathfrak {or, x = 72/3 = 24}$

The smallest no. is 24.

FOLLOW ME PLZ

Answer 2

Answer:

smallest number is 18

Step-by-step explanation:

Let the three consecutive multiples of 9 be

9(x-1),9(x),9(x+1)

sum=81

9(x-1+x+x+1)=81

9(3x)=81

27x=81

x=81/27

x=3

9(3-1),9(3),9(3+1)

9(2),9(3),9(4)

18,27,36

Hope this helps you

Mark as Brainliest answer please