the sum of three consecutive multiples of 9 is 888. find multiples
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9x + 9(x+1) + 9 (x+2) = 888
9x + 9x + 9 + 9x + 18 = 888
27x = 888 - 27
27x = 861
x = 287/9
so, first multiple is 9x = 9×287/9 = 287
second multiple is 9x+9 = (9×287/9) + 9 = 287 + 9 = 296
third multiple is 9x+18 = (9×287/9) + 18 = 287 + 18 = 305
9x + 9x + 9 + 9x + 18 = 888
27x = 888 - 27
27x = 861
x = 287/9
so, first multiple is 9x = 9×287/9 = 287
second multiple is 9x+9 = (9×287/9) + 9 = 287 + 9 = 296
third multiple is 9x+18 = (9×287/9) + 18 = 287 + 18 = 305
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