the sum of three consecutive multiples of 9 is 999.find these multiples
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The sum of three consecutive multiples of 9 is 999.Find these multiples.
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1st: 9(x-1) = 9x-9
2nd: 9x
3rd: 9(x+1) = 9x+9
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Equation:
sum = 999
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27x = 999
x = 37
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1st: 333-9 = 324
2nd: 333
3rd: 333+9 = 342
Answered by
2
Let the three multiples of 9 be x,x+9,x+18
It is given that the um of these three consecutive multiples is 999
x+x+9+x+18=999
=3x+26=999
=3x=999-27
=3x=972
=x=972= 324
so, the three consecutive multiples of 9 are 324 +9=333,333+9=342.
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