Question

the sum of three consecutive multiples of 9 is 999.find these multiples​

Answer 1

The sum of three consecutive multiples of 9 is 999.Find these multiples.

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1st: 9(x-1) = 9x-9

2nd: 9x

3rd: 9(x+1) = 9x+9

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Equation:

sum = 999

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27x = 999

x = 37

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1st: 333-9 = 324

2nd: 333

3rd: 333+9 = 342

Answer 2

Let the three multiples of 9 be x,x+9,x+18

It is given that the um of these three consecutive multiples is 999

x+x+9+x+18=999

=3x+26=999

=3x=999-27

=3x=972

=x=972= 324

so, the three consecutive multiples of 9 are 324 +9=333,333+9=342.

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