Question

the sum of three consecutive multiples of 9 is 999 find these multiples

Answer 1

let the first no. to be x
other no. are x + 9 and x + 18
so their sum will be = 999
x + x +9 + x + 18 = 999
3x + 27 = 999
3x = 999 - 27
3x = 972
x = 972 /3
x = 324
first no . is 324
another one is 324 + 9= 333
last no. is 324 + 18 = 342
so 324 ,, 333 ,, 342 are the three consecutive multiples of nine which add upto 999

Answer 2

Answer:

1st: 324

2nd: 333

3rd:  342

Step-by-step explanation:

1st: 9(x-1) = 9x-9

2nd: 9x

3rd: 9(x+1) = 9x+9

Equation:

sum = 999

27x = 999

x = 37

1st: 333-9 = 324

2nd: 333

3rd: 333+9 = 342

Hope it helps u.