Question

The sum of three consecutive multiples of 9 is 999.Find the numbers

Answer 1

let the first no. to be x
other no. are x + 9 and x + 18
so their sum will be = 999
x + x +9 + x + 18 = 999
3x + 27 = 999 
3x = 999 - 27
3x = 972
x = 972 /3
x = 324 
first no . is 324 
another one is 324 + 9= 333
last no. is 324 + 18 = 342 
so 324 ,, 333 ,, 342 are the three consecutive multiples of nine which add upto 999
 

Answer 2

x,x+9,x+18
now adding these 3x+27=999
solve it