Question

the sum of three consecutive multiples of 9 is 999 find the multiplies

Answer 1

let three multiples be x, x+9,x+18

x+ x+9+ x+18 =999
3x+ 27=999
3x= 972
x=324

324,333,342

Answer 2

hey mate the answer is

let the numbers be x,9+x,18+x

x+9+x+18+x=999
3x+27=999
3x=999-27
3x=972
x=972/3=324

x=324
x+9=324+9=333
x+18=324+18=342

hope it might help you