the sum of three consecutive multiples of 9 is 999 find the multiplies
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Answered by
7
let three multiples be x, x+9,x+18
x+ x+9+ x+18 =999
3x+ 27=999
3x= 972
x=324
324,333,342
x+ x+9+ x+18 =999
3x+ 27=999
3x= 972
x=324
324,333,342
Answered by
3
hey mate the answer is
let the numbers be x,9+x,18+x
x+9+x+18+x=999
3x+27=999
3x=999-27
3x=972
x=972/3=324
x=324
x+9=324+9=333
x+18=324+18=342
hope it might help you
let the numbers be x,9+x,18+x
x+9+x+18+x=999
3x+27=999
3x=999-27
3x=972
x=972/3=324
x=324
x+9=324+9=333
x+18=324+18=342
hope it might help you
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