Question

the sum of three consecutive multiples of 9 is567,f find the largest of these numbers​

Answer 1

Answer: 1st= 180,2nd = 189,3rd= 198

Step-by-step explanation:

Let three consecutive multiple of 9 are x,x+1,x+2

then , (x+x+1+x+2)×9=567

x=20

Let the numbers be x,x+9(9×1),x+18(9×2)

x+x+9+x+18=567

3x+27=567

3x=567-27

=540

x=540/3

=180

x=180

x+9=180+9

=189

x+18=180+18

=198

180+189+198=567

Answer 2

Answer:

let the three consecutive multiples be x,x+1 and x+2

then as we are given that ,

x+x+1+x+2 = 567

3x + 3 = 567

3x = 567-3 = 564

x = 564/3 = 188