the sum of three consecutive multiples of 9 is999.find these multiples
Answers
Answered by
4
Heya !!
Here is your answer.
Given :
Sum of three Consecutive multiples of 9 is 999.
Let the first multiple be x.
Second multiple = x + 9
Third multiple = x + 18.
ATQ
x + (x+9) + (x+18) = 999
3x + 27 = 999
3x = 972
x = 324.
Second multiple = 324+9 = 333
And, third multiple = 324+18 = 342
Hope You Got It
Here is your answer.
Given :
Sum of three Consecutive multiples of 9 is 999.
Let the first multiple be x.
Second multiple = x + 9
Third multiple = x + 18.
ATQ
x + (x+9) + (x+18) = 999
3x + 27 = 999
3x = 972
x = 324.
Second multiple = 324+9 = 333
And, third multiple = 324+18 = 342
Hope You Got It
RehanAhmadXLX:
:-)
Answered by
3
Heya !!!!
Let the consecutive multiples of 9 be (X) , (X+9) and (X +18)
According to question,
Sum of these numbers = 999
X + X + 9 + X + 18 = 999
3X + 27 = 999
3X = 999 -27
3X = 972
X = 972/3
X = 324
First Number = X = 324
Second number = X + 9 = 324 + 9 = 333
and,
Third Number = X + 18 = 324 + 18 = 342.
HOPE IT WILL HELP YOU...... :-)
Let the consecutive multiples of 9 be (X) , (X+9) and (X +18)
According to question,
Sum of these numbers = 999
X + X + 9 + X + 18 = 999
3X + 27 = 999
3X = 999 -27
3X = 972
X = 972/3
X = 324
First Number = X = 324
Second number = X + 9 = 324 + 9 = 333
and,
Third Number = X + 18 = 324 + 18 = 342.
HOPE IT WILL HELP YOU...... :-)
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