Question

The sum of three consecutive multiples os 8 is 888 find the multiple​

Answer 1

Answer:

[(5

−1

×3

−1

)

−1

÷6

−1

]

=[(5

−1×−1

)×(3

−1×−1

)]÷6

−1

=[5×3]÷6

−1

=[15×6]=90

Answer 2

Solution:

Let the three consecutive multiples of 8 be 8x, 8x + 8 and 8x + 16.

As per the conditions, we get

8x + (8x + 8) + (8x + 16) = 888

⇒ 8x + 8x + 8 + 8x + 16 = 888

⇒ 24x + 24 = 888

⇒ 24x = 888 – 24 (transposing 24 to RHS)

⇒ 24x = 864

⇒ x = 864 ÷ 24 (transposing 24 to RHS)

⇒ x = 36

Thus, the required multiples are

36 × 8 = 288, 36 × 8 + 8 = 296 and 36 × 8 + 16 = 304,

i.e., 288, 296 and 304.