Question

the sum of three consecutive multiplies of 11 is 1023 . find them

Answer 1

Answer:

Let the first number be x

then...

second number= x+11

third number = x+22

x+x+11+x+22 = 1023

3x+33 = 1023

3x=1023-33

3x= 990

x = 990/3

  =330

so numbers are...

x=330

x+11 = 341

x+22 = 352

30x11 =330

31x11 = 341

32x11 = 352

so all are multiple of 11.

Answer 2

Answer:

Let the three numbers be

• 11x
• 11x + 11
• 11(x+2)

→ 11x + 11x + 11 + 11 + 22 = 1023

→ 33x + 33 = 1023

→ 33x = 1023 - 33

→ 33x = 990

→ x = 990/33

→ x = 30

Now, by using the value of x -

• 11x = 11×30 = 330
• 11x + 11 = 11×30 + 11 = 341
• 11x (x+2) = 11×32 = 352

Therefore, the numbers are 330, 341 and 352.