Question

The sum of three consecutive multiplies of 11 is 297.find the numbers

Answer 1

let 3 consecutive terms are=
a, a+11,a+22....
a+a+11+a+22=297
3a+33=297
3a=297-33
3a=264
a=264/3
a=88
so three terms are...
a=88,a+11=88+11=99,a+22=88+22=110..