Question

the sum of three consecutive multiplies of 11 is 363. find these multiplies ​

Answer 1

Answer:

Let the three consecutive multiples of 11 are 11x, 11x+11 and 11x+22

Their sum is 363

11x+11x+11+11x+22=363

33x+33=363

33x=330

x=10

Step-by-step explanation:

First multiple =11x=11×10=110

Second multiple =11x+11=110+11=121

Third multiple =11x+22=110+22=132

Answer 2

$\huge\mathbb\colorbox{black}{\color{lime} {Question}}$

• $\sf\red{find \: the \: Multiples}$

$\huge\mathbb\colorbox{black}{\color{lime} {Answer}}$

• $\sf\red{110, 121 \: and \: 132.}$

$\small\mathbb\colorbox{black}{\color{lime} {Solution \: for \: the \: correct \: answer}}$

$\sf\red{Step \: 1}$

• Consider first multiple to be x.

• It is known that multiples of 11 differ by 11.

• So, second multiple is x + 11.

• And, third multiple is x + 22.

According to the question, linear equation formed is given by -

• x + (x +11) + (x+22) = 363

$\sf\red{Step \: 2}$

• Calculate value of x using equation formed -

• x + (x +11) + (x + 22) = 363

• 3x + 33 = 363

• 3x = 363-33
• x= 330 /3

• x= 110

$\sf\red{Step 3}$

• Calculate other multiples using value of X

• first multiple, x = 110
• second multiple,x + 11 = 121
• third multiple, +22= 132

Final Answer

• Hence, the 3 consecutive multiples of 11 whose sum is 363 are 110, 121 and 132.

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