Question

the sum of three consecutive multiplies of 11is 363 then find the
three
numbers.​

Answer 1

Answer:

11×10=110

11×12=121

11×13=132

110+121+132 = 363

Answer 2

Let the three multiples of 11 be 11x, 11x + 11 and 11x + 11 + 11 (= 11x + 22)

Their sum is = 363

A/q

11x + 11x + 11 + 11x + 22 = 363

=> 33x + 33 = 363

=> 33x = 363 - 33 = 330

=> x = 330/33 = 10

Therefore, the three numbers are

• 11x = 11 * 10 = 110
• 11x + 11 = (11 * 10) + 11 = 121
• 11x + 22 = (11 * 10) + 22 = 132