Question

The sum of three consecutive multiplies of 7 is 777. Find these multiples

Answer 1

Given the  three consecutive multiples of 7 are 'x' , 'x+7' , 'x+14'

Their sum = x+x+7+x+14 = 777 

                ⇒ 3x + 21 = 777

                ⇒ 3x = 777-21 = 756 

                ⇒ x = 756/3 = 252 .

Therefore three consecutive multiples of 7 are (x) = 252

                                                            252 + 7=259

                                                      252+14=266

Answer 2

Let three numbers be a-1, a, and a+1.

Multiply them by seven. We have 7(a-1), 7a, 7(a+1). These are consecutive multiples of 7.

The sum is equal to 777. It could be written as:

→ 7(a-1)+7a+7(a+1)=777

→ 21a=777

Without finding a value, we could find 7a instead and solve directly:

→ 7a=259

We are looking for 7a-7, 7a, and 7a+7. Three consecutive multiples are 252, 259, and 266 respectively.

Therefore the answer is 252, 259, and 266.