Question

the sum of three consecutive multiplies of 8 is 888.find the multiplies.​

Answer 1

SOLUTION :

The sum of three consecutive multiples of 8 = 888

Let the numbers be x, x + 8 and x + 16

According to the problem,

x + (x + 8) + (x + 16) = 888

x + x + 8 + x + 16 = 888

3x + 24 = 888

3x = 888 - 24

3x = 864

x = 864/3

x = 288

One of the multiple = 288

Remaining Multiples :

x + 8 = (288) + 8 = 296

x + 16 = (288) + 16 = 304

Therefore, the multiples are 288, 296 and 304.

Answer 2

Answer:Let 3 consecutive multiples of 8=x , x+8, x+16

There sum is 888

x+x+8+x+16=888

3x+24=888

3x=888-24

3x=864

x=864/3

x=288

Hence the no.s are 288, 296 and 304

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Step-by-step explanation: