Question

The sum of three consecutive multiplies of 8 is 888 , find the multiplies

Answer 1

Given : -

The sum of three consecutive multiplies of 8 is 888 , find the multiplies

To find : -

Find the multiples

Solution : -

Let the first multiple be 8x. Then , the next two multiple will be 8(x+1) and 8(x+2)

According to the given condition

It is given that the sum of these three consecutive multiple is 888

$\therefore$ 8x + 8(x+1) + 8(x+2) = 888

=> 8x + 8x + 8 + 8x + 16 = 888

=> 24x + 24 = 888

=> 24x = 888 - 24

=> 24x = 864

=> x = 864/24 = 36

$\large{\boxed{\bf{x = 36}}}$

So,

First multiple = 8x = 8 × 36 = 288

Second multiple = 8(x+1)=8(36+1)=296

Third multiple = 8(x+2) = 8(36+2) = 304

Verification : -

Sum of three multiples obtained

= 288 + 296 + 304

= 888

Hence, the solution is verified

Answer 2

$\huge\green{\underline{\underline{\bf{\green{Given}}}}}$

• Sum of three consecutive multiples of 8 = 888

$\huge\green{\underline{\underline{\bf{\green{To\:Find}}}}}$

• Three consecutive Multiples of 8

$\huge\green{\underline{\underline{\bf{\green{Solution}}}}}$

Let the,

• First multiple of 8 be x

Then,

• Second Multiple = 8(x + 1)

• Third Multiple = 8(x + 2)

Now,

According to Question :-

=> 8x + 8(x + 1) + 8(x + 2) = 888

=> 8 ( x + (x + 1) + (x + 2) = 888

=> x + x + 1 + x + 2 = 888/8

=> 3x + 3 = 111

=> 3x = 111 - 3

=> x = 108/3 = 36

Then,

• First multiple = 8x = 8 × 36 = 288

• Second multiple = 8 (x+1) = 8(36+1) = 8×37 = 296

• Third multiple = 8(x + 2) = 8(36 + 2) = 8 × 38 = 304