the sum of three consecutive multiplies of 9 is 999 find these multiples
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we find the multiples when firstly we start the solution let the first digit x , x +1 , x + 2
x+(x+1)+(x+2)=999
+x+1x+2 = 999
3x+3 = 999
3x = 999-3
3x = 996
x=996/3
x+1=332+1 = 333
x+2 = 332+2= 334
hope it will help you
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