the sum of three consecutive multiplies of 9 is 999 find these multipleslo
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Let consecutive numbers be x, x+1, x+2
9(x+x+1+x+2)=999
x=36
Answered by
2
given that :
the sum of three consecutive multiple of 9 is 999 .
we have to find the numbers .
solution:-
let. the first multiple of 9 = 9x
because these are consecutive .
then
2nd number = 9(x+1)
3rd number = 9(x+2)
Now,
According to question:
9x +9(x+1) + 9(x+2) = 999
=> 27x +27 = 999
=> 27x = 999-27 = 972
=> x = 36
hence;
1st number multiple of 9 = 9× 36 = 324
2nd number multiple of 9 = 9×37 = 333
3rd number multiple of 9 =9× 38 = 342
Answer:
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