Question

the sum of three consecutive munltiples of 7is63.find these munltiple
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Answer 1

Answer:

7x+14x+21x=63

42x=63

x=63/42

x=3/2

Step-by-step explanation:

7x=7×3/2=21/2__ans

14x=14×3/2=21_ans

21x=21×3/2=63/2___ans

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Answer 2

Let,

$\bold{the \: {1}^{st } number \: be \: x}$

$\bold{the \: {2}^{nd} number \: be \: x + 7}$

$\bold{the \: {3}^{rd \: }number \: be \: x + 7 + 7}$

Then,

$\bold{A/q\:\: x + (x + 7)+(x + 7 + 7) =63 }$

$\bold{ \implies \: x + x + 7 + x + 7 + 7 = 63}$

$\bold{ \implies \: x + x + x = 63 - 7 - 7 - 7}$

$\bold{ \implies \: 3x = 63 - 21}$

$\bold{ \implies \: 3x = 42}$

$\bold{ \implies \:x = \frac{42}{3} }$

$\bold{ \implies \:x = 14 }$

$\bold{By \: putting \: the \: value \: of \: x } \\ \\ \bold{the \: {1}^{st} number = x = 14}$

$\bold{the \: {2}^{nd} \: number \: = x + 7}\\\\ \bold{ = 14 + 7 = 21 }$

$\bold{the \: {3}^{rd }number = x + 7 + 7 }\\\\ \bold{= 14 + 7 + 7 = 28 }$