Question

The sum of three consecutive muntiples of 11 is 363. find these muntiples?​

Answer 1

Let the consecutive no. be x , x + 1 and x+2

As given ,

x + (x+1) + (x + 2) = 363

3x+ 3 = 363

3x = 363 - 3

x = 360 ÷ 3

x = 120

x + 1 = 121

x + 2 = 122

so the three consecutive no are 120 , 121 and 122 .

Hope it was helpful : ) : )

Answer 2

Question :–

The sum of three consecutive multiples of 11 is 363. find these multiples?

Given :–

• Three consecutive multiples of 11.
• The product of the number is 363.

To Find :–

• Find the three multiples.

Solution :–

Let, the three consecutive multiples of 11 be :–

11x, 11(x + 1), 11(x + 2).

ATQ,

→ 11x + 11(x + 1) + 11(x + 2) = 363

[ First we need to find the value of x ]

[Now, Open the brackets]

→ 11x + 11x + 11 + 11x + 22 = 363

→ 33x + 33 = 363

→ 33x = 363 + 33

→ 33x = 330

→ x = $\sf \dfrac{\cancel{330}}{\cancel{33}}$

→ $\boxed{ \sf \green{x = 10}}$

Hence,

The three multiples are:-

1. 11x = 11 × 10 = 110
2. 11(x + 1) = 11(10 + 1) = 11 × 11 = 121
3. 11(x + 2) = 11(10 + 2) = 11 × 12 = 132