Question

the sum of three consecutive mutiples of 3 is 72 find the numbers​

Answer 1

Answer:

let the First multiple be x

x+ x+3+x+6=72

3x +9=72

3x=72-9

3x=63

x=63/3

x=21

therefore: 21,24 &27 are three consecutive multiples of 3

Answer 2

x+x+3+x+6=72

3x+9=72

3x=72-9

3x=63

x=63/3

x=21

so, consecutive no 1= x=21

consecutive no 2 = x+3 = 21+3=24

consecutive no 3= x+6= 21+6=27