Question

The sum of
three consecutive mutliple of 3 is 126. find the mutliples.​

Answer 1

let 3 consecutive and multiple of 3 be 3x 3(x+1) 3(x+2)

now

3x +3(x+1) +3(x+2) =126

3[x +x+1+x+2] =126

3(3x+3)=126

9x+9=126

9x=126-9

x= 117÷9

x= 13

therefore x=13

3x =39

3(x+1)=3*14=42

3(x+2)=3*15=45

checking answer

39+42+45= 126

answer is absolutely correct now you can do

thank u