Question

the sum of three consecutive
muttiples 6 8 is 888. Eirich the
multiples​

Answer 1

Answer:

let multiples be X+8,X+16 and X+24

according to the question

X+8 +X+16+X+24=888

3x+48=888

3x=888-48

3x=840

X=840/3

X=280

X+8=280+8=288

X+16=280+16=296

X+24=280+24=304

Explanation:

hope it helps you

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Answer 2

you can follow this method, apply 8 instead of 68 so you can easily understand the sum