Question

The sum of three consecutive Muttiples of
4 is 444 find these multiples how ​

Answer 1

Step-by-step explanation:

Let the first multiple of of 4 be x

Then second multiple is x + 4

Then third multiple will be x + 8 ( As they are consecutive multiples of 4)

So according to question

x + x + 4 + x + 8 = 444

3x +12 = 444

3x = 432

x = 432/3

x = 144

First multiple of 4 is x = 144

Second multiple of 4 is x + 4 = 144 + 4 = 148

Third multiple of 4 is x + 8 = 144 + 8 = 152

144+148+152=444

Hope this would have cleared your doubt.

Answer 2

$\large\sf\blue{ANSWER}$

GIVEN

• Sum of three consecutive multiples of 4 is 44

TO FIND:-

• Multiples of 4.

Now,

let the multiples be x

$\implies\textbf{First\:Multiple=4x}$

$\implies\textbf{Second\:Multiple=4(x+1)}$

$\implies\textbf{Third\:multiple=4(x+2)}$

Atq.

$\implies\textbf{4x+4(x+1)+4(x+2)=444}$

$\implies\textbf{4x+4x+4+4x+8=444}$

$\implies\textbf{12x=444-12}$

$\implies\textbf{12x=432}$

$\implies\textbf{x=36}$

Hence, The multiples (4×36),4(36+1),4(36+2) i.e 144,148,152.