Question

the sum of three consecutive natual numbers is 33. what are the nymbers?

Answer 1

Let the numbers be a, a+ 1 and a + 2

According to question,

a + a + 1 + a + 2 = 33

=> 3a + 3 = 33

=> 3a = 30

=> a = 10

First number = 10

Second number = 11

Third number = 12

Answer 2

x+x+1+x+2=33
3x+3=33
3x=33-3
X=30/3
x=10
x+1=11
x+2=12



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