Question

The sum of three consecutive natural number is 114.Find the numbers.

Answer 1

let one no. be x
second no. be x+1
third no.=x+2

so

x+x+1+x+2=114
3x+3=114
3x=114-3
3x=111
x=37

so first no. =x=37
second no.=x+1=37+1=38
third no.=x+2=37+2=39

Answer 2

Hey mate,
Here's your answer
=> let one no.be x, then another will be x+1 and x+2.
According to the question,
X+(x+1)+(x+2)=114
X+x+1+x+2=114
3x+3=114
3x=114-3
3x=111
X=111/3
X=37

Therefore, 1st no. Is x=37
2nd no. Is x+1=37+1=38
3rd no. Is x+2=37+2=39.

Thus, 3 consecutive nos. Are 37,38&39.

Hope it helps you!!
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