The sum of three consecutive natural number is 33.What are the numbers?
Answers
Step-by-step explanation:
Three consecutive numbers can be expressed as a central number n, with one less than the central number (n-1) and one more than the central number (n+1)
If we do this, then we see that the +1 and -1 add to zero, so the sum can also be expressed as 3n
(n-1)+n+(n+1)=3n
The number n, then, is one third of this sum
n=3n/3
We know that the sum of the three numbers is equal to 33
3n=33
So from our work above we see that if we divide 33, the sum of the three, by three, we get our central number n
33/3=11
The three consecutive numbers must be 11 minus one, 11, and 11 plus one.
11–1=10
11=11
11+1=12
So, the three numbers are 10, 11, and 12
Checking our work
10 is even, 11 is odd, 12 is even
10+11+12=33
Seems legit
Bonus note:
33 is an odd number
Three consecutive natural numbers can either be
Odd, even, odd (results in an even sum)
Even, odd, even (results in an odd sum)
So this series must be of the latter variety.
This is not important to the calculation.
Answer:
10,11,12
Step-by-step explanation:
x+x+1+x+2=33
3x+3=33
3x=33-3
x=30/3
x=10
so the no.s are 10,11,12
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