Question

The sum of three consecutive natural number is 63. Then find the numbers.
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Answer 1

Let the three consecutive natural numbers be

x, x + 1 and x + 2

Given, their sum = 63

According to the question,

$\sf\implies x + x + 1 + x + 2 = 63 \\\sf\implies 3x + 3 = 63 \\\sf \implies3x = 63-3 \\\sf\implies3x = 60 \\ \\ \sf \implies x = \frac{60}{3} \: \\ \\ { \boxed { x = 20}}$

1st number => x

$\pink:\implies$ 20

2nd number => x + 1

$\pink:\implies$ 20 + 1

$\pink:\implies$ 21

3rd number => x + 2

$\pink:\implies$ 20 + 2

$\pink:\implies$ 22

Answer 2

Step-by-step explanation:

Let the first natural number = x

Let the second natural number = x + 2

Let the third natural number = x + 4

Acc to the condition

x + x + 2 + x + 4 = 63

3x + 6 = 63

3x = 63 - 6

3x = 57

x = 57/3

x = 19

First number = 19

second number = 19 + 2 = 21

third number = 19 + 4 = 23

$hope \: it \: helps \: you$